Question

A man buys certain number of orange at 20 per rupee and equal number of orange at 30. He mixed them and sold at 25 per rupee. Find his gain or loss percent.

Answer 1

Step-by-step explanation:

He buys x oranges at 20 for Rs.60/-

Each orange will cost 60/20 or Rs.3/-

So cost price of this variety of orange =3x

Similarly he buys x (same quantity) at 30 for Rs.60/-. So cost per orange 60/30 or Rs.2/-

So CP of the 2nd variety = 2x

Total quantity of both varieties :3x+2x = 5x

Total cost of both varieties = Rs.120/-

5x = Rs.120, x = 24

So his average CP is he buys 24 oranges for Rs.60/- or CP per orange =60/24 or 5/2

He sells at 25 oranges for Rs 60 or SP per orange = 60/25 or 12/5

Loss = CP-SP = 5/2-12/5=1/10

Loss Percent = loss/CP x 100

1/10 ÷5/2 x 100 = 1/10×2/5×100 = 4% loss.