Question

A body projected vertically up with certain velocity reaches a maximum height of 75m another body with double the mass is thrown up with double the initial velocity the maximum height reached by it would be option a 100m option b 150 m option c 225m option d 300m which is correct answer

Answer 1

Irrespective of mass H

max

=u

2

/2g=50m

if we double the initial velocity u then H

max

will get 4 times means 200m .

Answer 2

Answer:

A body projected vertically up with a certain velocity reaches a maximum height of 75m another body with double the mass is thrown up with double the initial velocity the maximum height reached by it would be $300m$

Explanation:

• We have an equation of motion connecting initial velocity (u), final velocity (v), displacement (s), and acceleration(a) of a moving body as

         $V^{2} =u^{2} +2as$

• it is independent of the mass of the body

• The final of a body at maximum height is zero

From the question, we have

maximum height reaches by the first body $s_{1}=75m$

⇒

$0=u^{2}+2a*75\\\frac{u^{2} }{2a} =75$

the initial velocity of the second body $=2u$

⇒$0=(2u)^{2} +2as_{2} \\\\s_{2} =4u^{2}/2a =4*s_{1}=4*75=300m$

therefore the maximum height of the second body is $300m$