Question

a body projected vertically with a velocity u from the ground. its velocity at 1/3 rd of maximum height is​

Answer 1

Explanation:

Correct option is

D

2

u

For a body projected up,

H

max

=

2g

u

2

By equation

v

2

=u

2

−2gh

Putting, h=

2

H

max

=

4g

u

2

v

2

=u

2

−2gv

2

=u

2

−2g

4g

u

2

=u

2

−

2

u

2

v

2

=

2

u

2

v=

2

u