Question

a body projected with a velocity 50 m/s distance travelled in 6 th second is cg=10m/s^2

Answer 1

I hope..it will help u......

Answer 2

Answer:

Distance travelled in sixth second will be 5 metre.

Explanation:

U = 50 metre

Ta = u/g= 50/10 = 5 sec

After 5 seconds the velocity of the body becomes zero so distance travelled in 6th second is distance travelled between 5 second and 6 second applying Newton's Law of Motion

$\mathrm{s}=\mathrm{ut}+1 / 2 \mathrm{at}^{2}$ (since initial velocity is zero hence ut = 0)

$\begin{array}{l}{\Rightarrow \mathrm{s}=1 / 2 \mathrm{at}^{2}} \\ {\mathrm{S}=1 / 2 \times 10 \times(1) \mathrm{X}(1)}\end{array}$

s=5m