Question

A body released from height 'h' takes time 't'to reach the ground. After time 1/2,its height from the ground is

Answer 1

Answer:

1/4h

Explanation:

If  a body is released from a height which is falling freely then initial velocity is zero unless mentioned and because the objects falls in the direction of gravity so g is positive.

u=0, Height=h, g=+10ms-2, Time = t

using (ii) equation of motion,

h=ut +1/2g$t^{2}$

= 1/2x 10x $t^{2}$

h= 5$t^{2}$

t= $\sqrt{h/5}$

At t= 1/2t

h'= ut +1/2g$(t/2)^{2}$

h'= 1/2 x 10 x 1/4 x h/5 = 1/4h

Answer 2

Answer:

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