A body released from hight h take time t to reach the earth surface. Calculate the time taken by same body to reach the surface of the moon.
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Answered by
12
FOR A FREELY FALLING BODY FROM A HEIGHT H,
T =√(2H/G)
AS IN MOON G IS 1/6th TIMES OF EARTH
T=√{2H/(G/6)}
=>T=√(12H/G)
T =√(2H/G)
AS IN MOON G IS 1/6th TIMES OF EARTH
T=√{2H/(G/6)}
=>T=√(12H/G)
aditya17072004:
hi
Answered by
16
let t be the time taken by the body on earth
so,
h = 1/2 g t^2
t^2 = 2h/g
t= √2h/gv .... (1)
let x be the time taken by the body on moon
but g on moon is g/6
so
x = √2h/g/6
x = √6*2h/g
x = √6 * √2h/g
from (1)
x = √6 t
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