A body released from rest falls freely from a height h' to the ground. Its average velocity for the motion is:
Answers
Answer:
I’m guessing that your body is on Earth.
The equation of motion you can use here is Vf = Vi + at where Vf is final velocity, Vi is initial velocity, a is acceleration, and t is time.
Let’s plug in the numbers. Vi can be 0 m/s because the object is dropped, a can 9.8 m/s^2 because that is the acceleration due to gravity, t is one second.
Vf = 0m/s + 9.8m/s*1s
Vf = 9.8 m/s.
However, for a problem this simple, it’s better to look at what acceleration actually means. When the acceleration is 9.8 m/s^2, it means that the velocity of the object increases by 9.8 m/s every second. So if the object has a velocity of 0 m/s now, it will have a velocity of 9.8 m/s in 1 second.
Explanation:
Answer:
s=h
g=10m/s2
u=0
v2= 2gs
v2=2*10*h
v2= 20h
v=√20
v=4.47
hope it helps you