Question

A bomb is dropped from an aeroplane when it is at a height h directly above a target. If the aeroplane is moving horizontally at a speed v, the distance by which the bomb will miss the target is given by

Answer 1

This question is based on concept of horizontal projectile motion.

velocity of aeroplane in horizontal direction = v

so, velocity of bomb, $v_b=v$

height of aeroplane from the target = h

as we know, acceleration along horizontal direction is zero.

so, distance covered by bomb in horizontal direction, x = vt.

now, distance covered by bomb in vertical direction, y = 0 + 1/2 gt²

or, h = 1/2gt²

or, t = √(2h/g)

so, x = vt = v√(2h/g)

so, distance covered by bomb by which it will miss the target is x = v√(2h/g)

Answer 2

Answer:

We will use the formula t=(2h/g)^1/2 then distance=velocityxtime

Explanation: