Question

a body revolves with constant speed v in a circular path of radius r theagnitude of its average acceleration during motion between the two point in diametrically opposite direction

Answer 1

Final Answer : $\frac{2v^2}{\pi r}$

Steps:
1) Average Acceleration = Change in velocity between two points / Time taken.

2) At diametrically opposite points ,
Velocity at point C is v (-i) .
Velocity at point E is v (i)

3)Time taken,t = Distance Arc(CE)/ Speed
=πr/v


Average Acceleration = v(i)-v(-i) / t
= 2v(i) / πr/v = 2v^2/πr

Answer 2

Answer:

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✌️ Khushi ✌️