A body rotating with uniform angular acceleration covers 100 in the first 5s after the start. Its angular speed at the end of 5s is?
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Answered by
320
General formula
θ = ω₀t + 0.5αt²
Substitute the known values
100 rad = 0 + [0.5 × α × (5 s)²]
α = 100 rad / (0.5 × 25 s²)
α = 8 rad/s²
Now, Angular speed after 5 seconds is
ω = ω₀ + αt
= 0 + (8 rad/s² × 5 s)
= 40 rad/s
Angular speed after 5 seconds is 40 rad/s
[Note: I assumed that it covers 100 rad in first 5 seconds as unit is not mentioned in the question]
θ = ω₀t + 0.5αt²
Substitute the known values
100 rad = 0 + [0.5 × α × (5 s)²]
α = 100 rad / (0.5 × 25 s²)
α = 8 rad/s²
Now, Angular speed after 5 seconds is
ω = ω₀ + αt
= 0 + (8 rad/s² × 5 s)
= 40 rad/s
Angular speed after 5 seconds is 40 rad/s
[Note: I assumed that it covers 100 rad in first 5 seconds as unit is not mentioned in the question]
Answered by
72
Answer:
The correct answer is 40π.
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