a body start from rest and moves with a uniform acceleration of 2m/s².what will be it's velocity and displacement at the end of 10 second
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Answer:
Displacement = 200 m
Velocity = 20 m/s
Explanation:
a = 2 m/s^2
t = 10 s
u = 0 m/s^2
v - u = at = 2 m/s^2 × 10 s = 20 m/s
=> v = 20 m/s + 0 m/s = 20 m/s
S = vt = 20 m/s × 10 s = 200 m
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Question:-
- A body start from rest and moves with a uniform acceleration of 2m/s².what will be it's velocity and displacement at the end of 10 second.
Given:-
- Body starts from rest ( u = 0 )
- Moves with an acceleration of 2m/s²
- Time taken is 10 seconds
To Find:-
- Find the distance travelled and final velocity.
Solution:-
Here ,
- u = initial velocity
- v = final velocity
- s = distance
- a = acceleration
- t = time
Formula to be Used:-
- v = u + at
- s = ut + 1/2 at²
First ,
We have find the final velocity:-
⟹ v = u + at
⟹ v = 0 + 2( 10 )
⟹ v = 20m/s
Now ,
We have to find the distance:-
⟹ s = ut + 1/2 at²
⟹ s = 1/2 × 2 × 10²
⟹ s = 10 × 10
⟹ s = 100m
Hence ,
- Distance travelled is 100m
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