Question

A body start from rest with a uniform acceleration 3m/s^2. Find the distance covered by the body in 7s

Answer 1

d = vᵢt + 1/2at² ; where d = distance, vᵢ = initial velocity, a = acceleration, and t = time interval

Since vᵢ = 0, vᵢt = 0, the formula can be rewritten as:

d = 1/2at²

Knowns and Unknown

d = ? m

a = 3 m/s²

t = 8 s

Calculate the distance the body moves.

d = 3 m/s² × (8 s)²

d = 3 m/s² × 64 s²

d = 192 m

The body will move 192 m (200 m rounded to one significant figure).

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