a body start to slide on horizontal surface with an initial velocity of 0.5 m/s.due to friction it's velocity decrease at the rate of 0.05m/s ?
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Answered by
1
we know that
v = u +at
here
u = 0.5
a = -0.05 m/s
v = 0 m/s
so, time taken to stop will be
t = -u/a
= -0.5/-0.05
thus, t = 10s
v = u +at
here
u = 0.5
a = -0.05 m/s
v = 0 m/s
so, time taken to stop will be
t = -u/a
= -0.5/-0.05
thus, t = 10s
Answered by
0
Answer:10 second
Explanation:By using v=u+at
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