Question

A body started to move from rest and its uniform acceleration is 1.6m/s square. Calculate the final velocity and distance travelled by the body in two minutes.

Answer 1

ANSWER :

Given :

▪ Initial velocity of body=zero

▪ Acceleration of the body=1.6m/s$^2$

To Find :

▪ Velocity and distance travelled by the body in 2min.

Formula used :

▪ Since, acceleration is constant throughout the whole journey, we can apply equations of kinematics directly.

▪ First equation of kinematics :

☞ v = u + at

▪ Third equation of kinematics :

☞ s = ut + (1/2)at^2

▪ 2min = 120sec

Calculation :

• Final velocity

→ v = u + at

→ v = 0 + (1.6)(120)

→ v = 192m/s

• Distance travelled

→ s = ut + (1/2)at^2

→ s = 0(120) + [0.5×1.6×(120)^2]

→ s = 0.5×1.6×14400

→ s = 11520m = 11.52km