A body starting feom rest has an acceleration of 5m/s square. calculate the distance travelled by it in 4th second
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a=5m/s square
u=0m/s
t=4 s
As the body is moving in the straight line,
S=ut+1/2at square
S=0×4+1/2×5×16
S=0+8×5
S=40
Therefore, the distance travelled by it in 4th second is 40m
u=0m/s
t=4 s
As the body is moving in the straight line,
S=ut+1/2at square
S=0×4+1/2×5×16
S=0+8×5
S=40
Therefore, the distance travelled by it in 4th second is 40m
tasmiya05:
its not 40 i aslo got the same ans it is 17.5 given in my book
hey
I think the answer is wrong in ur book
ok
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