Question

A body starting from rest accelarates uniformily at the rate of 100 ms for 10 Seconds.calculate the final velocity at the end of 10 seconds and the distance traveled durin this interval?

Answer 1

Answer:

Given that, a = 100 m/s² , t = 10s , u = 0 m/s , v = ? and s = ?

We know that,

v = u + at      (first equation of motion)

ie, v = 0 + 100 × 10

      = 1000 m/s

Also we know that,

v² = u² + 2as

1000² = 0² + 2×100×s

1000000 = 0 + 200s

1000000 = 200 s

ie , s= 1000000/200

       = 5000 m

ie, velocity after 10 s = 1000m/s and distance covered after 10 s = 5000m

HOPE THIS HELPS......

Answer 2

Explanation:

u =0,a=100/10=10m/s^2 t=10sec

a=v-u/t

10=v-0/t =v/10

v=100m/s

s=(v+u/2)×t

s= (100/2)×10

s=50×10

s=500m