Question

A body starting from rest moves with constant acceleration. find ratio of body covered in 5th to that of 5 sec

Answer 1

Answer:

Ratio = 9 : 25

Explanation:

Given that,

Initial velocity = u = 0m/s

Acceleration = a m/s²

We know that,

Distance covered in nth second = u + a(2n - 1)/2

Distance covered in t seconds = S = ut + 1/2 at²

Hence,

Distance covered in 5 seconds = ut + 1/2 at²

                                                    = 0 + 1/2 * a * 5² = 25a/2

Distace coverd in 5th second = u + a(2n - 1)/2

                                                 = 0 + a(10 - 1)/2 = 9a/2

Therefore,

Ratio of distance covered in 5th second : distance covered in 5 seconds

= 9a/2 : 25a/2

= 9 : 25