Question

a body starting from rest moving with a constant acceleration covers 15m in 3sec. find the distance covered by it in 12sec​

Answer 1

Answer:

Given:-

Initial velocity ,u = 0m/s

Distance covered ,s = 15m

Time taken ,t = 3 s

To Find:-

Distance covered by it in 12 seconds

Solution:-

Using 2nd equation of motion

s = ut + ½at²

15 = 0×3 + ½×a × 3²

15 = 0 + 1/2 × a × 9

15×2 = 9 × a

30 = 9× a

a = 30/9

a = 10/3 m/s² 

Now, calculating the distance covered by body in 12 second

s = ut + 1/2 at²

s = 0 × 12 + 1/2 × 10/3 × 12²

s = 0 + 5/3 × 144

s = 5 × 48

s = 240 m

The distance covered by the body in 12 seconds is 240 metres

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Answer 2

Given:-

Initial velocity ,u = 0m/s

Distance covered ,s = 15m

Time taken ,t = 3 s

To Find:-

Distance covered by it in 12 second.

Solution:-

It is given that the body starts from rest and moving with a constant acceleration . We have to calculate the distance covered by it in 12 second . Firstly we calculate the acceleration of the body . Using 2nd equation of motion

s = ut + 1/2at²

where,

s denote distance covered

u denote initial velocity

t denote time taken

a denote acceleration

Substitute the value we get

15 = 0×3 + 1/2×a × 3²

15 = 0 + 1/2 × a × 9

15×2 = 9 × a

30 = 9× a

a = 30/9

a = 10/3 m/s² = 3.33 m/s²

Now, calculating the distance covered by body in 12 second . Again using 2nd equation of motion

s = ut + 1/2 at²

substitute the value we get

s = 0 × 12 + 1/2 × 10/3 × 12²

s = 0 + 5/3 × 144

s = 5 × 48

s = 240 m

Hence the distance covered by the body in 12 second is 240 metres

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