A body starting from rest travels with uniform acceleration. If it travels 100m in 5s, what is the value of acceleration?
Answers
Answer- The above question is from the chapter 'Kinematics'.
Some important terms and formulae:-
1. Velocity- It is the displacement per unit time.
S.I. Unit of Velocity- m/s
It is a vector quantity as it possesses magnitude and direction.
2. Acceleration- It is the rate of change of velocity.
S.I. Unit of Acceleration- m/s²
It is also a vector quantity.
Negative acceleration is called retardation.
3. Distance- It is the path length transversed by an object.
S.I. Unit of Distance- m
It is a scalar quantity.
4. Displacement- It is the shortest distance between the initial and final point.
S.I. Unit of Displacement- m
It is a vector quantity.
5. Equations for uniformly accelerated motion-
Let u = Initial velocity of a particle
v = Final velocity of a particle
t = Time taken
s = Distance travelled in the given time
a = Acceleration
1) v = u + at
2) s = at² + ut
3) v² - u² = 2as
Given question: A body starting from rest travels with uniform acceleration. If it travels 100 m in 5 s, what is the value of acceleration?
Answer: We are given that,
u = 0 m/s (Body was at rest)
s = 100 m
t = 5 s
Using 2nd equation of motion,
s = at² + ut
100 = a × 5² + 0 × 5
100 = a × 5²
100 ÷ 25 = a
a = 4 × 2
a = 8 m/s²
∴ Value of acceleration = 8 m/s².
Answer:
⠀⠀⠀⋆ Initial Velocity (u) = 0 m/s
⠀⠀⠀⋆ Distance Travelled (s) = 100 m
⠀⠀⠀⋆ Time Taken (t) = 5 seconds
⠀⠀⠀⋆ Acceleration (a) = ?
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