Question

A BODY STARTING FROM REST TRAVELS WITH UNIFORM ACCELERATION IF IT TRAVELS 100m IN 5s . find its acceleration

Answer 1

Answer:

Acceleration = 8 m/s²

Explanation:

Given that,

Distance = S = 100m

Time = t = 5s

Initial velocity = u = 0m/s (Body starts from rest)

Acceleration = a = ?

From Newton's Laws of motion,

$\boxed{S=ut+\frac{1}{2}at^{2} }$

Putting all the values in we get,

100 = 0*5 + 1/2 * a * 5²

100 = 1/2 * a * 25

a = 100 * 2/25

a = 200/25

a = 8 m/s²

Answer 2

Explanation:

${\red{\underline{\underline{\bold{Given:-}}}}}$

• Initial velocity = 0 m/s

• Distance travelled = 100m

• Time taken = 5 sec

${\blue{\underline{\underline{\bold{To\:Find:-}}}}}$

• The acceleration produced by the body

${\green{\underline{\underline{\bold{Solution:-}}}}}$

According to the second equation of motion :-

$\boxed{ \bf s = ut + \frac{1}{2}a {t}^{2} }$

Here:-

• s = distance travelled

• u = initial velocity

• t = time taken

• a = acceleration

Substituting the values:-

${ \implies\bf s = ut + \frac{1}{2}a {t}^{2} }$

${ \implies\bf 100 = 0(5)+ \dfrac{1}{2}a {(5)}^{2} }$

${ \implies\bf 100 = 0+ \dfrac{25}{2}a }$

${ \implies\bf 100 = \dfrac{25}{2}a }$

${ \implies\bf 100 \times 2 \: = \: 25a }$

${ \implies\bf \dfrac{200}{25} \: = \: a }$

$\implies\bf a \: \: = \: 8m /{s}^{2}$

$\boxed{\bf Acceleration \: \: = \: 8m/{s}^{2} }$