The 3rd term of an arithmetic sequence is 43 and 6th term 76 write first 3 term and find the 10 th term
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Answer:
The AP is 21,32,43........... and 10th term 120
Step-by-step explanation:
a3= 43
a3 =a+(3-1)d = a+2d = 43 ____(1)
a6 = 76
a6 = a +(6-1)d = a +5d = 76 ___(2)
From (1) and (2), By elimination method,
(2)-(1),
3d=33
d= 11
From (1) a+2d=43
a+2x11=43
a= 21
The Ap is a,a+d, a+2d, a+3d.......
that is, 21,21+11,21+2x11,21+3x11.........
21,32,43,........
a10= a+(10-1)d
=21+9x11
=120
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