Question

A body starting from rest travels with uniform acceleration. If it travels 200 m in 10 s, then the
value of the acceleration is_______m/s.
​

Answer 1

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

• Distance, s = 200 m

• Time, t = 10 sec

• Initial velocity, u = 0 m/s

$\;\;\underline{\textbf{\textsf{ To Find :-}}}$

• Acceleration, a

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

$\underline{\:\textsf{We know that, }}$

$\bigstar\;\underline{\boxed{\sf S=ut+\dfrac{1}{2}\;at^{2}}}$

$(\bf 2nd \: equation \: of \: motion)$

Where,

›› u = Initial velocity

›› t = Time

›› a = Acceleration

$\underline{\:\textsf{Putting the given values :-}}$

$\longrightarrow\sf S=0\times 10+\dfrac{1}{2}\times a \times (10)^{2}\\\\\\\longrightarrow\sf S=0+\dfrac{1}{2}\times a \times 100\\\\\\\longrightarrow\sf S=a\times 50\\\\\\\longrightarrow\sf 200 = 50\;a \ \ \ \ \\\\\\\longrightarrow\sf a =\dfrac{200}{50}\\\\\\\longrightarrow\sf a=4\\\\\\\longrightarrow \large{\underline{\boxed{\green{\sf a=4\;m/s^{2}}}}}$

$\;\;\underline{\textbf{\textsf{ Hence -}}}$

$\underline{\textsf{The acceleration is \textbf{ 4m/s²}}}.$

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$\;\;\underline{\textbf{\textsf{ Know More:-}}}$

$(\bf 1st\: equation \: of \: motion)$

•$\boxed{\sf v = u + at}$

$(\bf 2nd \: equation \: of \: motion)$

•$\boxed{\sf s = ut + \frac{1}{2} at^{2}}$

$(\bf 3rd \: equation \: of \: motion)$

•$\boxed{\sf v^{2} - u^{2} = 2as}$

Where,

›› s = Distance Covered

›› u = Initial Velocity

›› t = Time taken

›› v = Final Velocity

›› a = Acceleration

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Answer 2

Answer:

The initial velocity travelled is 625m

The accleration is α=10m/s

2

The time is t=5s

Apply the equation of motion

v=u+at

The velocity is v=0+10.5=50m/s.

The distance travelled in the first 5s is

s=ut+

2

1

at

2

=0.5+

2

1

.10.5

2

=125m

Thedistancetravelledinthefollowing10sis

s

1

=ut

1

=50.10=500m

Thetotaldistancetravelledis

d=s+s

1

=125+500=625m