Question

A body starts from point A with an initial velocity of 2 ms − 1 and with a constant acceleration of 5 / 2 ms − 2 . How much distance would it have travelled when the velocity has reached 10ms − 1 ?

Answer 1

Step-by-step explanation:

Initial velocity=2ms-1

final velocity=10ms-1

accelration=5/2 ms-2

from the equation of motion

v^2=u^2+2as

(10)^2=(2)^2+2*5/2*s

100-4=5s

5s=96

s=96/5

hence the distance travelled is=96/5