Question

A body starts from rest and acquires a speed of 36 km/hr in 2 seconds. Calculate the
acceleration acting on it & the distance travelled by it during this time?

Answer 1

Answer:

Explanation:

Verified Answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but Verified Answers are the finest of the finest.

Since,

V = 0 + at (by formula)

or a = V/T

So, at any time ‘t’ the velocity is,

v = 0 + at

or v = (V/T)t

Therefore, KE of the body after time t is,

KE = ½ (mv2)

or KE = ½ m[(V/T)t]2

Answer 2

Answer:

1. Acceleration = 5 m/s² ;

2. Distance Travelled = 10 m.

Explanation:

Speed = 36 km/hr Or,

= (36*5/18) m/s

= 10 m/s

Assuming that the body moves on a straight line,

Initial Velocity (u) = 0 m/s

Final Velocity (v) = 10 m/s

Time (t) = 2 s

i. Acceleration (a) = (v-u)/t

= 10/2 m/s²

= 5 m/s²

ii. Distance Travelled (S) = ut+1/2at²

= (0*2) + (0.5*5*2*2)

= 10 m

Hope this helps.