A body starts from rest and gains a velocity of 6 m/s in 2s of time. Find the acceleration of the body and its average velocity for the given time:
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Answered by
16
Acceleration = 6-0 / 2 = 3m/s square
Ave. Velocity = 6/2=3m/s.....
Ave. Velocity = 6/2=3m/s.....
Answered by
18
acceleration = velocity gained or lost/ the time in which the change occured.
Note:Velocity is a vector quantity so even the direction matters that is why u get a negative sign sometimes where as speed is a scalar.
so here acc = 6/2 = 3m/s^2 ( ^ - power)
average velocity = displacement / time
disp = - 1/2(a * (t ^ 2)) that is s = u * t - (1/2) a* (t^2) here u = 0
= 6
so average velocity = 6/2 = 3
so both are 3 here
Note:Velocity is a vector quantity so even the direction matters that is why u get a negative sign sometimes where as speed is a scalar.
so here acc = 6/2 = 3m/s^2 ( ^ - power)
average velocity = displacement / time
disp = - 1/2(a * (t ^ 2)) that is s = u * t - (1/2) a* (t^2) here u = 0
= 6
so average velocity = 6/2 = 3
so both are 3 here
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