A body starts from rest and has an acceleration 20m/sec square.Then what is the distance covered by the body in first 8 sec?
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distance will be 640m
Answered by
1
Let s is distance covered by body
Body start from rest so u=0
s= ut+ 1/2at^2
s= 0+ 1/2×20× 8^2
s= 640m
Body start from rest so u=0
s= ut+ 1/2at^2
s= 0+ 1/2×20× 8^2
s= 640m
rohit4k:
you mark me my answer is also correct
Tq karan and rohit for helping me
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