Question

A body starts from rest and having a acceleration of 5 metre per second square calculate the distance travelled by it in 4 seconds

Answer 1

hey buddy !! here's your answer...

we have 2nd formula for motion,

s = ut + 1/2at^2
where,

s =is distance travelled
u =initial velocity
a =acceleration
t= time

in the above question u = 0

s = 0(t) + 1/2 at^2
s = 1/2 x 5 x (4)^2
s = 5 x 4 x 2
hence we get

✔️s = 40 m

hope it helps !! ❤️✌️

Answer 2

HEYA!!
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Given that ,

Initial Velocity U = 0. [ As body starts from Rest ]

Acceleration A = 5 m/s^2

Time T = 4 seconds .

Distance Travelled S =?

Using the Second Equation of Motion ,


S = UT + 1/2 AT^2


S = 0 × 4 + 1/2 × 5 × 16

S = 1/2 × 5 × 16

S = 40 m.


✨Hence Distance Travelled in 4th seconds is 40 m


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