Question

A body starts from rest and is uniformly accelerated for 30 sec . the distance travelled in the first 10 sec is x1 next is x2 and last 10 sec is x3 . then the ratio of x1 : x2 : x3 will be ........?

Answer 1

the ratios of distance travelled is 1:3:5

Answer 2

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HERE IS UR ANSWER;-

The applicable kinematic expression is 

s=ut+12at2


s is distance traveled in time t, u is initial velocity and a is acceleration.

Distance traveled in first 10s

x1=0×10+12a×102

⇒x1=50a

Distance traveled in next 10s

x2=s20−s10=(0×20+12a×202)−50a

⇒x2=200a−50a=150a

Distance traveled in last 10s

x3=s30−s20=(0×30+12a×302)−200a

⇒x3=450a−200a=250a

the required ratio is 

x1:x2:x3=50a:150a:250a

⇒x1:x2:x3=1:3:5

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