Question

A body starts from rest and maves with a unform acceleration of 10m/s2 what is the distance travelled at the end of 5 second

Answer 1

Uniform acceleration of body (a) = 10 m/s^2

Initial velocity = 0 m/s

Let the distance traveled by the body in 10 seconds be s.

Time of motion = 5 s

Now, By using second equation of motion:

$\( s = v_i \times t + \frac{1}{2} \times a \times t^2\)$

$\( s = 0 \times 5 + \frac{1}{2} \times 10 \times 5^2\)$

$\( s = 0 + 5 \times 25\)$

s = 125 m

Hence, the distance traveled by the body in 5 seconds is 125 m.