Question

a body starts from rest and moves it with constant acceleration prove that its instantaneous velocity varies directly as the square root of its displacement

Answer 1

HOPE THIS WILL HELP U .

Answer 2

Answer:

yes

Explanation:

You can derive that from the following kinematics equation : v^2 = u^2 + 2as, where v is the velocity at any distance s, u is the initial velocity which is zero here, a is the acceleration, and s is the distance traversed. So let's solve it : v^2 = 2as (as u^2 = 0), which gives you the following equation : v = (2as)^1/2. Since a will be a given constant here and 2 is a constant, we can rewrite the equation as v = k • s^1/2 [where k is a constant for a given acceleration : k = (2a)^1/2]. So you can see here that v is directly proportional to the square root of any given distance, or v varies with the square root of the distance travelled, which means the same thing ! Kaiser T, MD.