Question

A body starts from rest and moves with a uniform acceleration of 5m/s. Distance travelled at the end of 20s

Answer 1

Answer:

1000m or 1km

Explanation:

Given that,

a= 5m/s^2

u(initial velocity)= 0m/s. (because the body is starting from rest)

Distance can be calculated by the formula

$s = \: ut + \frac{1}{2} a {t}^{2}$

Putting values of u, t and a in the formula, we get

$s = 0 \times 20 + \frac{1}{2} \times 5 \times 20 \times 20$

$s = \frac{1}{2} \times 5 \times 20 \times 20$

Cancelling 2 and 20, we get

s= 1×5×10×20= 1000 m/s

Answer 2

Answer:

Ans,

if u have to find Distance from the above question,

is

Explanation:

Initial velocity,

o m/s

Uniform acceleration,

5m/s

time,

20sec

Distance(s),

s=ut + 1/2 a(t)square

s=(0)(20)+(5)(20)square

s=0+(5)(400)

s=0+2000

s=2000m

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