Question

A body starts from rest and moves with a uniform acceleration of 5m/s2 for 5s and then it moves with a constant velocity for 4s. Later it slows down and comes to rest in 5s. Draw the velocity graph for the motion of the body and answer the following questions:a) What is the maximum velocity attended by the body?b) What is the distance travelled during this period of acceleration?c) What is the distance travelled when the body was moving with constant velocity?d) What is the negative acceleration of the body while slowing down?e) What is the distance travelled by negative acceleration?f) What is the total distance travelled?

Answer 1

1. u=0m/s
v=?
t=5sec
acce.=5m/s^2
v=u+at
o+5×5
25m/s
2.S=ut+1/2at^2
=0×5+1/2×5×5^2
= 0+1/2×125
= 62.5
3.the body is constant so there is no acce.
Now s=ut+1/2at^2
s=25×4+1/2×0×4^2
100+0
100m
4.retardation=u=25m/s,v=0m/s,t=5s
=0-25/5
=-5m/s^2
5.distance travel by retarding
v^2-u^2=2as
0^2-25^2=2×-5×s
0-625=-10s
-625=-10s
-625/-10=s
62.5m=s
6.total d travelled=
area of triangle +area of rectangle+are area of triangle
1/2×b×h+b×h+1/2×b×h
1/2×125×100+1/2×125
=225m
May this help u
Best of luck.

Answer 2

Answer:

14. A body starts from rest and moves

with a uniform acceleration of 5m/s2 for

5s and then it moves

with a constant velocity for 4s. Later it

slows down and comes to rest in 5s. Draw

the velocity-time graph for the motion of

the body and answer the following

questions: a) What is the maximum

velocity attained by the body?

b) What is the distance travelled during

this period of acceleration?

c) What is distance travelled when the

body was moving with constant velocity?

d) What is the retardation of the body

while slowing down? e) What is the distance travelled by

retarding?

f) What is the total distance travelled?