Physics, asked by harleenkaur8230, 1 year ago

A body starts from rest and moves with a uniform acceleration of 2 m/s2 until it travels a distance of 100m, find the velocity of the body?

Answers

Answered by Mylo2145

Heya...!✌️❤️
Here is ur answer..!✌️❤️
$u = 0m {s}^{ - 1}$
$a = 2 {ms}^{ - 2}$
$s = 100m$
${v}^{2} - {u}^{2} = 2as$
${v}^{2} - 0 = 2(2)(100) \\ {v}^{2} = 400 \\ v = \sqrt{2 \times 2 \times 10 \times 10} \\ v = 2 \times 10 \\ v = 20 {ms}^{ - 1}$
Hope it is acceptable....!✌️❤️
#MarkAsBrainliest
VIDHI☺️

Mylo2145: it is never specified to use a particular equation in physics

Mylo2145: u always hv to go according to the data given

Mylo2145: u can also send this question link to the moderators n ask if this is wrong

BrainlyPromoter: Yes, she is right!

BrainlyPromoter: We have to use the equation according to the information available to us in the question

BrainlyPromoter: If you still have doubts then tell :)

Mylo2145: thnku so much☺️

Mylo2145: u helped me once again

BrainlyPromoter: welcome dear

Mylo2145: ✌️

Answered by Ash042

Answer:

20m/s

Explanation:

Given,

Initial velocity, u = 0 m s/

Final velocity, v = ?

Acceleration = $2 m/s^{2}$

Distance , s = 100m

By the Third equation of Motion

$v^{2} - u^{2} = 2as$

v² - 0 = 2 × 2 × 100

v² = 400

v = √400 = 20m/s

Final velocity of the body is 50 m/s.

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