Question

A body starts from rest and moves with a uniform acceleration of 2m/s^2. If it travels a distance of 100m find the velocity of the body

Answer 1

According to the third
equation
Vsq=usq+2as
Vsq=0+2*2*100
Vsq=400
V=20
$\sqrt{400 =}$

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Final\:velocity=20\:m/s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a car initially at rest starts moving with a constant acceleration car initially at rest starts moving with a constant accelerationof 2m/s2 and travels at a distance of 100m.

• We have to find Final velocity of car.

$\green{\underline\bold{Given :}} \\ :\implies \text{Initial\:velocity(u)=0 m/s} \\ \\ :\implies \text{Acceleration(a)= 2\:m/s}^{2} \\ \\ :\implies \text{Distance(s)= 100\:m} \\ \\ \red{\underline \bold{To \: Find : }} \\ :\implies \text{Final\:velocity= ?}$

• According to given question :

$\bold{Using \: Third\: equation \: of \: motion : } \\ : \implies v^{2} = u^{2} + 2as\\ \\ : \implies v^{2}= 0 + 2\times 2\times 100 \\ \\ : \implies v^{2}= 400 \\\\ : \implies v= \sqrt{400} \\ \\ \green{ :\implies \text{v=20 \: m/s}}$