A body starts from rest and moves with an acceleration of 4ms-2 .
(a) In what time the body will acquire a speed of 80m/s?
(b) How much distance will it travel in this time?
Answers
Answered by
2
initial velocity (u) :- 0m/s
acceleration (a) :- 4m/s -²
(a) final velocity (v) :- 80m/s
time (t) :- ?
v = u + at (eq 1)
t = v-u/a
t = 80 - 0 /4
t = 80 / 4
t = 20
ans) time taken is 20 seconds
(b) s = ut + 1/2 at²
distance = (0)(20) + 1/2 (4)(20)(20)
distance = 0 + 800
ans ) distance traveled in this time is 800 m.
acceleration (a) :- 4m/s -²
(a) final velocity (v) :- 80m/s
time (t) :- ?
v = u + at (eq 1)
t = v-u/a
t = 80 - 0 /4
t = 80 / 4
t = 20
ans) time taken is 20 seconds
(b) s = ut + 1/2 at²
distance = (0)(20) + 1/2 (4)(20)(20)
distance = 0 + 800
ans ) distance traveled in this time is 800 m.
Answered by
1
v=80m/s u=0 a=4m/s²
(a) v=u+ at ---(1)
substituting the values in (1) you get t=20s
(b) s=ut+at²/2 ---(2)
substituting the values in (2) you get s=800m
Hope this helped you...
(a) v=u+ at ---(1)
substituting the values in (1) you get t=20s
(b) s=ut+at²/2 ---(2)
substituting the values in (2) you get s=800m
Hope this helped you...
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