Physics, asked by ShaniKat9979, 1 year ago

A body starts from rest and moves with uniform acceleration. If it acquires a velocity of 80 m/sec in 20 sec.find the distance covered by it 20 second.

Answers

Answered by Anonymous
153

\Huge\underline{\underline{\sf Answer}}

\large\underline{\underline{\sf Distance\:covered\:in\:20sec}}

\large\underline{\underline{\sf is\:800m}}

\Huge\underline{\underline{\sf Solution}}

\large\underline{\underline{\sf Given:}}

  • Initial velocity (u) = 0

  • Final Velocity (v) = 80m/s

  • Time (t) = 20 sec

\large\underline{\underline{\sf To\:Find:}}

  • Distance (d) = ?

_______________________________________

\large{\boxed{\sf v=u+at}}

\large\implies{\sf 80=0+a×20}

\large\implies{\sf a=\frac{80}{20}}

\Large\implies{\sf a=4m/s^2}

Now ,

\large{\boxed{\sf s=ut+\frac12at^2}}

\large\implies{\sf s=0+\frac12×4×(20)^2}

\large\implies{\sf s=800m }

Hence ,

\large\underline{\underline{\sf Distance\:covered\:in\:20sec}}

\large\underline{\underline{\sf is\:800m}}

Answered by muscardinus
2

The distance covered by the body in 20 seconds is 800 meters.

Explanation:

Given that,

Initial velocity of the body, u = 0

Final velocity of the body, v = 80 m/s

Time, t = 20 s

Let a is the uniform acceleration of the body. It can be calculated using first equation of motion as :

a=\dfrac{v-u}{t}

a=\dfrac{80-u}{20}

a=4\ m/s^2

Let d is the distance covered by the body in 20 seconds. Using the second equation of motion as :

d=ut+\dfrac{1}{2}at^2

d=\dfrac{1}{2}at^2

d=\dfrac{1}{2}\times 4\times 20^2

d = 800 m

So, the distance covered by the body in 20 seconds is 800 meters.

Learn more :

Topic : Equation of kinematics

https://brainly.in/question/6397825

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