Question

At her maximum height a girl in a swing is 3m above the ground and at the lowest point she is 2m above the ground what is her maximum velo

Answer 1

The maximum velocity of the swing is 4.42 m/s.

Explanation:

It is given that,

Maximum height of a girl, h = 3 m

Lowest position of the girl, h' = 2 m

The swing will come down to a height of 3-2 = 1 m from the highest point.

Let v is the maximum velocity of the swing. Using the conservation of energy as :

$\dfrac{1}{2}mv^2=mgH$

$v=\sqrt{2gH}$

$v=\sqrt{2\times 9.8\ m/s^2\times 1\ m}$

v = 4.42 m/s

So, the maximum velocity of the swing is 4.42 m/s. Hence, this is the required solution.

Learn more,

The conservation of energy

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