A body starts from rest and moves with uniform acceleration. What is the ratio of kinetic energies at the end of 1st , 2nd and 3rd seconds of its journey ?
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Answer:
1:4:9
Explanation:
kinetic energy (ek) = 1/2 mv^2
ek is directly proportional to v^2 ........ 1
after 1st sec v=at (as u=0)
as v directly proportional to t.......... 2
from 1 and 2 ek directly proportional to t^2
so 1st:2nd:3rd=1^2:2^2:3^2=1:4:9
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