A body starts from rest and moves with uniform acceleration of 6 m/s. What distance does it cover after 3 seconds?
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By one of the formula of kinematics ,
s= ut + 1/2 at²
where s is the distance covered
u is the initial speed or velocity
a is the acceleration and
t is the time taken.
Here,
u = 0 (. body starts from rest)
a= 6m/s²
and t = 3 sec
we have to find s.
s = ut + 1/2 at²
s= (0)(3) + 1/2 (6)(3)²
s= 1/2 (6)(9)
s= 27 m
Here is your answer !
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