Question

a body starts from rest and moves with uniform acceleration of 10 for 5 sec. during the next 10 sec it moves with uniform velocity. find total distance travelled by body.(using graphical analysis)​

Answer 1

Explanation:

starts from rest so u=0

given a =10 and for t=5 sec

so from v=u+at

so velocity will be= 0+(10×5)=50m/s

so distance1 = 50×5=250 m

again it moves with v=50m/s for t =10 sec.

so distance 2 = 50×10=500m

total distance=500+250=750 m