Question

A body starts from rest and reaches a speed of 5 m.s peer square second after traveling with uniform acceleration in a straight line for 2 s. Calculate the acceleration of the body.​

Answer 1

Answer:

Here We get the values

u = 0 m/s(initial velocity)

v =5m/s(Final velocity)

t=2s (time)

Acceleration = Final velocity - Initial Velocity/ Time

Or a= v-u/t

Hence substituting all values we get --------

5-0/2 = 5/2 =

$2m {s}^{ - 2} \: or \: 2 \frac{m}{ {s}^{2} }$