A body starts from rest and uniformly accelerated it travels distance x,in time t second.shows that the distance travelled in the t'th second of it's motion is , s'th=(2/t-1/r2)x
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Answer:
x1=21at2x2+x1=21a(2t)2=4x1=x2=3x1x1+x2+x3=21a(3t)2=9x1x3=9x1−x1−3x1=5x1∴1:3:5
Hence,
option (C) is correct answer
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