Question

a body starts from rest and with a uniform acceleration of 10m/s² for 5 seconds .During the next 10 seconds it moves with uniform velocity . The total distance travelled by the body is

Answer 1

By 2nd law of motion

S=ut+1/2at^2

S=(10×5)+1/2(5)(5^2)

S=50+62.5=112.5m

initial velocity, u= 10m/s. Acceleration, a= 5 m/s^2. Time interval t=5s. Eq. of motion: d= ut+(1/2) at^2. d=10X5 +(1/2)X5X25 =50+62.5=112.5 m

Answer 2

first put newtons 1st law of motion yo will get vvelocity is 50m/s then take 0m/s as u snd t=5 then apply newtons 3rd law of motion you will get answer as 525meters