A body starts from rest in a straight line with an acceleration of 8.0m/s2.Draw its time-velocity graph and determine:(i)Velocity of the body after 5 seconds. (ii) How much distance does the body has moved in first 5 seconds? (iii) What average velocity of the body is during this time?
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Answered by
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Hey.
Here is the answer.
a = 8 m/s^2
i) u = 0 ; t = 5 s
As v = u + a t
so, v = 0+ 8×5 = 40 m/s
ii) Also, s = u t + 1/2 a t^2
so, s = 0 + 1/2×8×5^2 = 100 m
iii) average velocity = (u + v)/2
= (0+40)/2
=20m/s
____________________________
The V-t graph will be a straight line starting from origin inclined to time axis such that a = 8m/s^2 and V= 40 m/s at t = 5s
____________________________
Thanks .
Here is the answer.
a = 8 m/s^2
i) u = 0 ; t = 5 s
As v = u + a t
so, v = 0+ 8×5 = 40 m/s
ii) Also, s = u t + 1/2 a t^2
so, s = 0 + 1/2×8×5^2 = 100 m
iii) average velocity = (u + v)/2
= (0+40)/2
=20m/s
____________________________
The V-t graph will be a straight line starting from origin inclined to time axis such that a = 8m/s^2 and V= 40 m/s at t = 5s
____________________________
Thanks .
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5
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