Question

A body starts from rest is moving under a constant acceleration up to 20 sec. If it moves S, distance in first 10 sec
and S, distance in next 10 sec. then S, will be equal to :
​

Answer 1

Answer:

3s1

Step-by-step explanation:

a=a

t=10s

S10=S1=21at2=21a(10)2

=50a

v1=at=10a

t=20s

S20(S2+S1)=21at2=21a(20)2=200a

S2=200a−S1=150a

S1S2=3.

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