A body starts from rest its displacement is proportional to time square at constant?
Answers
Answered by
0
From the derived equations of kinematic motion of objects, we derived the equations keeping the acceleration of the object constant.
So, by the second equation of motion,
s= ut+1/2*at^2
So, if u = 0 (initial velocity as it starts from rest)
S = 1/2*a*t^2
So, clearly displacement is proportional to t^2 at constant a i.e constant acceleration.
So, by the second equation of motion,
s= ut+1/2*at^2
So, if u = 0 (initial velocity as it starts from rest)
S = 1/2*a*t^2
So, clearly displacement is proportional to t^2 at constant a i.e constant acceleration.
Similar questions