Question

A body starts from rest moves with a uniform acceleration of 0.1ms-2 for 2 minutes. Find a speed aquired and b the distance travelled

Answer 1

Answer:

12 m/s

Explanation:

u = 0

a = 0.1 m/s²

t = 2 mins = 120 secs

Using equation of motion-

v = u + at

» v = 0 + 0.1 * 120

» v = 12 m/s

Hence, answer is 12 m/s.

Answer 2

Answer:

$\large{\underline{\boxed{\sf Speed = \: 12 \: m/s}}}$

$\large{\underline{\boxed{\sf Distance = 720 \: m}}}$

Explanation:

Given that ;

Initial velocity, u = 0 m/s

Acceleration, a = 0.1 m/s

Time taken, t = 2 mins

Converting the time from minutes to seconds -

⇒ Time = 2 * 60 = 120 secs

To find the speed acquired, we will use first equation of motion ;

v = u + at

⇒ v = 0 + 0.1 * 120

⇒ v = 12 m/s

Hence, the speed of body is 12m/s.

_______________________

To find the distance travelled, we will use third equation of motion -

$\sf S = ut + \frac{1}{2}at^2 \\\\\sf S = 0 * 120 + \frac{1}{2} * 0.1 * 120 *120\\\\\sf S = 0 + 0.1*60*120 \\\\ \sf S = 720 \: m$

Hence, the distance travelled is 720m.