Question

A body starting from rest moves with constant acceleration.The ratio of distance covered by the body during the 6th sec to that covered in 6sec is

Answer 1

Answer:

11/36

Explanation:

distance covered in 6th second=distance covered in 6s-distance covered in 5 s

u=0

distance covered in 6s= ut +1/2at^2=0+36a/2=36a/2

distance covered in 5s= ut + 1/2at^2=0+25a/2=25a/2

distance covered in 6th sec=36a/2-25a/2=a/2 (36-25)=11a/2

required ratio=11a/2÷36a/2=11/36