a body starts from rest moving with an acceleration a=2m/s for some time and agter achieving a max velocity starts retarding at the rate of 4m/s^2 and finally comes to rest and if the total time taken is 30sec then max velocity attained is
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at first
u is 0
therefore v is equal to at which becomes 2t at a is given 2
so t becomes v/2
now for second
v is 0 and u is v that's final velocity or max velocity of previous
so as v=u+ at
so 0=v+4t
so t=v./4 as it can't be negative
add both time and put it equal to 30
the answer is 40m/s
u is 0
therefore v is equal to at which becomes 2t at a is given 2
so t becomes v/2
now for second
v is 0 and u is v that's final velocity or max velocity of previous
so as v=u+ at
so 0=v+4t
so t=v./4 as it can't be negative
add both time and put it equal to 30
the answer is 40m/s
Answered by
0
Ans12
Explanation:
t(xy)/x+y
t=10s
x=2 m/s
y=3m/s
10(2x3)/2+3
= 60/5
= 12 mls
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