Question

a body starts from rest of mass 100 gram with force 50 N in 10 sec what is the distance traveled
​

Answer 1

Given:-

• Initial velocity ,u = 0m/s

• Force ,F = 50 N

• Time taken ,t = 10 s

• Mass ,m = 100g = 100/1000 = 0.1 kg

To Find:-

• Distance Travelled ,s

Solution:-

As we know that Force is the product of mass and Acceleration.

• F = ma

Substitute the value we get

→ 50 = 0.1 × a

→ a = 50/0.1

→ a = 500m/s²

Now , using 2nd equation of motion

• s = ut + 1/2at²

Substitute the value we get

→ s = 0×10 + 1/2×500 × 10²

→ s = 0 + 250 × 100

→ s = 25000

→ s = 25000/1000

→ s = 25 km

Therefore, the distance covered by the body is 25 Kilometres.

Answer 2

$\huge\fcolorbox{red}{cyan}{25 \:km}$

Explanation:

• Mass (m)=>100 g = 0.1kg
• Force Applied (f)= 50 N
• Time Taken (t)= 10 s
• Distance Travelled (s)= ?
• Acceleration(a) = ?

First Lets Calculate The Acceleration :-

$\bf\color{purple}{Force=Mass \times Acceleration} \\ =>\bf{Lets\:Put\:The\:Values} \\ =>50=0.1 \times a \\ => a = \frac{50}{0.1} \\ => \boxed{500\:m/s²}$

Thus The Acceleration is 500m/s²

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Now Lets Calculate The Distance Travelled :-

From Second Equation Of Motion :-

$\bf\color{orange}{s=ut+\frac{1}{2}at²} \\ =>\bf{Lets\:Put\:The\:Values} \\ =>s = (0 \times 10) + (\frac{1}{2} \times 500 \times 10²) \\ => s = 0 + (250 \times 100) \\ =>\boxed{s = 25000\:m}</p><p>$

Hope it helped